14. 60. g of naoh is dissolved in enough distilled water to make 300 ml of a stock solution. what volumes of this solution and distilled water, when mixed, will result in a solution that is approximately 1 m naoh?

The question is incomplete, the complete question is attached below.

Answer : The volumes of stock solution and distilled water will be, 20 mL and 80 mL respectively.

Explanation : Given,

Mass of NaOH = 60 g

Volume of stock solution = 300 mL

Molar mass of NaOH = 40 g/mol

First we have to calculate the molarity of stock solution.

Now put all the given values in this formula, we get:

Now we have to determine the volume of stock solution and distilled water mixed.

Formula used :

where,

are the molarity and volume of stock solution.

are the molarity and volume of diluted solution.

From data (A) :

Putting values in above equation, we get:

Volume of stock solution = 20 mL

Volume of distilled water = 100 mL - 20 mL = 80 mL

From data (B) :

Putting values in above equation, we get:

Volume of stock solution = 20 mL

Volume of distilled water = 100 mL - 20 mL = 80 mL

From data (C) :

Putting values in above equation, we get:

Volume of stock solution = 60 mL

Volume of distilled water = 300 mL - 60 mL = 240 mL

From data (D) :

Putting values in above equation, we get:

Volume of stock solution = 60 mL

Volume of distilled water = 300 mL - 60 mL = 240 mL

From this we conclude that, when 20 mL stock solution and 80 mL distilled water mixed then it will result in a solution that is approximately 1 M NaOH.

Hence, the volumes of stock solution and distilled water will be, 20 mL and 80 mL respectively.

state the principle of separating two immiscible liquids by separating funnel. describe an activity with diagram to separate a mixture of water and kerosene oil. answer: immiscible layers separate out in layers depending on their densities in separating funne