How many atoms of oxygen are in 4.6 grams of copper sulfate

m(CuSO4×5H2O)=424.0 g

M(CuSO4×5H2O)=249.68 g/mol

n=m/M

n(CuSO4×5H2O)=1.7 mol

There are 9 atoms of oxygen in each formula unit of CuSO4×5H2O. Therefore,

n(O)=8.5 mol

M(O)=16 g/mol

m=M×n

m(O)=135.6 g

Explanation:

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