A0.20 mol sample of mgcl(s) and a 0.10 mol sample of kcl(s) are dissolved in water and diluted to 500 ml. what is the concentration of cl- in the solution?

0.6 Molar

Explanation:

According to the Question,

In 500 mL of water ,

0.2 mol sample of MgCl is present and 0.1 mol of KCl is present.

Thus ,

Concentration of Cl anion in the solution will be the sum of Cl anion concentration from MgCl and KCl.

From MgCl , 0.2 mol of Cl anion will come and 0.1 mol of KCl anion will come ,

Thus , 0.3 mol of Cl anion will come totally .

So, Cl anion concentration will be = 0.6 M

it is the most commonly accepted one

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