What is the energy needed to raise 2.004g of water from 89.0°c to 139.0°c?

The answer to your question is E = 419.435 J

Explanation:

Data

Mass = m = 2.004 g

Temperature 1 = T1 = 89°C

Temperature 2 = T2 = 139°C

Specific heat  of water = Cp = 4.186 J/g°C

Energy = E = ?

Formula

E = mCp(T2 - T1)

Substitution

E = (2.004)(4.186)(139 - 89)

Simplification and result

E = 8.3887(50)

E = 419.435 J

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