Asample of oxygen gas (o2) has a volume of 7.51 l at a temperature of 19°c and a pressure of 1.38 atm. calculate the moles of o2 molecules present in this gas sample. a. 0.217 mol b. 0.866 mol c. 6.65 mol d. 0.433 mol =n

The moles of O₂ which are present in the sample are 0.433. (option D)

Explanation:

We should apply the Ideal Gases Law, to solve this:

P . V = n. R. T

1.38 atm . 7.51L = n . 0.082 . 292K

(1.38 atm . 7.51L) / (0.082 . 292K) = n

0.433 moles = n

solute : a solute is a substance that is dissolved in another substance is known as a solvent. it is mixed with a special mixture know as homogeneous mixture.

solvent: a solvent is a substance that dissolved a solute, which results in a solution is known as solvent.