If 63.99 ml of ba(oh)2 is required to neutralize 56.3 ml of 0.0410 molar hcl, what is the molarity of the ba(oh)2 ?

0.0181 M

Explanation:

Let's consider the following neutralization reaction.

2 HCl + Ba(OH)₂ → BaCl₂ + 2 H₂O

56.3 mL of 0.0410 M HCl react. The moles of HCl are:

0.0563 L × 0.0410 mol/L = 2.31 × 10⁻³ mol

The molar ratio of HCl to Ba(OH)₂ is 2:1. The moles of Ba(OH)₂ are:

1/2 × 2.31 × 10⁻³ mol = 1.16 × 10⁻³ mol

There are 1.16 × 10⁻³ mol of Ba(OH)₂ in 63.99 mL. The molarity of Ba(OH)₂ is:

1.16 × 10⁻³ mol/ 63.99 × 10⁻³ L = 0.0181 M

pv=nrt

explanation:

if the temperature drops and becomes cool

then the atmosphere can be freezing as the water vapor in the air is at maximum (100%) and can be severely cold

also can be snowing lightly as the moisture in the air will start to solidify

and btw this is not chemistry but