Calculate the root mean square (rms) average speed of the atoms in a sample of xenon gas at 0.17atm and −52.°c .

round your answer to 3 significant digits.

Check explanation

Explanation:

NB: In this question, we need the mass which is not given,so we have to make assumptions for the mass of xenon.

V^2(rms)= 3KT/m(1).

Where k= Boltzmann's constant =1.381×10^−23 m^2.kg/s^2.K.

T= temperature of the gas (in Kelvin), m= mass of one molecule of the gas (in kg).

Temperature, T= 273+(-52) =221K and V= the root mean square (rms).

Assuming that one mole of the gas has ;

m=0.084 kg. Hence, the mass of one molecule using Avagadro's number is;

0.084 kg ÷ 6.02×10^23 molecule.

Therefore, mass,m= 1.395× 10^ -25.

Therefore, from equation one above, we have;

V^2(rms)= 3 × 1.381×10^-23×221k/1.395×10^25.

V^2(rms) = 9.15603×10^-21/ 1.395×10^-25.

V(rms)= √ 6.56346236559139× 10^−46.

V(rms)= 2.56×10^-23 m/s.

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

the answer would be b i believe