Chemistry, 26.12.2019 19:31 Taylor73836
When 1 mol each of c2h5oh and ch3co2h are allowed to react in 1 l of the solvent dioxane, equilibrium is established when 13 mol of each of the reactants remains. calculate the equilibrium constant for the reaction. (note: water is a solute in this reaction.)
Answers: 2
![Keq=\frac{[CH_3CO_2C_2H_5]\cdot [H_2O]}{[C_2H_5OH]\cdot [CH_3CO_2H]}](/tpl/images/0433/9199/a2445.png)
![Keq=\frac{[CH_3CO_2C_2H_5]\cdot [H_2O]}{[C_2H_5OH]\cdot [CH_3CO_2H]}=\frac{2/3\cdot 2/3}{1/3\cdot 1/3}=4](/tpl/images/0433/9199/d5707.png)
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When 1 mol each of c2h5oh and ch3co2h are allowed to react in 1 l of the solvent dioxane, equilibriu...
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