Calculate the amount of work done, in joules, when 2.5 mole of h2o vaporizes at 1.0 atm and 25°c. assume the volume of liquid h2o is negligible compared to that of vapor. (1 l·atm = 101.3 j)

6.195 x 10 3 J oule

Explanation:

all given values

Temperature =25+ 273= 298K

Pressure= 1 atm

ideal gas constant = R=0.0821 L.atm/K/mol

number of moles n= 2.5

volume =?

using ideal gas equation

PV=nRT

for volume V=nRT/P

=2.5×.0821×298/1

=61.16 L

As the direction of work done is opposite to the direction of motion so work done will be negative  

W=-PV

=-1atm× 61.16 L

=101.3× 61.61

 = - 6195.96 J

= 6.195 x 10 3 J

in chemistry, adhesion and cohesion are attractive forces that exist between molecules. they hold the molecules together from each other. they are different in that adhesive force exists between molecules of different substance while cohesive force happens between molecules of same substance.

adhesion between water and glass causes water molecules at the edge of water and glass interface to climb up the wall in a narrow glass tube. this is called capillary action. cohesion is what gives glass its shape and causes water to form a droplet.