The clectron in a hydrogen atom, originally in level n=9, undergoes a transition to a lower level by emitting a photon

of wavelength 384 nm. what is the final level of the electron?

c = 3.00 x 10 m/s,

h = 6.626 x 10^-34j-s,

rh= 2.179 x 10^-18

Explanation:

The given data is as follows.

            = 9,           = ?

              Z for hydrogen = 1

As we know that,

                       Energy (E) =

where,   h = planck's constant = Js

              c = speed of light = m/s

          = wavelength

According to Reydberg's equation, we will calculate the energy emitted by the photon as follows.

or,     =

Putting the given values into the above equation as follows.

          =

        =  

                   n = 2

Thus, we can conclude that the final level of the electron is 2.

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.