a 0.0733 l balloon contains 0.00230 mol of l, vapor at a pressure of 0.924 atm.
what is the temperature, in kelvin, of the i in the balloon?
express the answer using 3 significant figures.

T = 350 K

Explanation:

Given data:

Volume of balloon = 0.0733 L

Number of moles = 0.00230 mol

Pressure = 0.924 atm

Temperature in K = ?

Solution:

PV = nRT

PV / nR = T

T = 0.924 atm × 0.0733 L / 0.00230 mol × 0.0821 atm. L/mol. K

T = 0.07 / 0.0002 /K

T = 350 K

i think it is d. e because the next one is igneous.