Aphoton with 2.3 ev of energy can eject an electron from potassium. what is the corresponding wavelength of this type of light? answer in nm. 1 ev = 1.60 x 10-19 j speed of light = 3.0 x 108 m/s planck's constant = 6.626 x 10-34 js socratic.

Explanation:

Given that:

The energy of the photon = 2.3 eV

Energy in eV can be converted to energy in J as:

1 eV = 1.60 × 10⁻¹⁹ J

So, Energy =

Considering

Where,  

h is Plank's constant having value

c is the speed of light having value

is the wavelength of the light being bombarded

Thus,  

Also,  

1 m = 10⁻⁹ nm

So,  

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

the correct answer would be d. hope this !