A51.24-g sample of ba(oh)2 is dissolved in enough water to make 1.20 liters of solution. how many ml of this solution must be diluted with water in order to make 1.00 liter of 0.100 molar ba(oh)2 ?

0.40 L

Explanation:

Calculation of the moles of as:-

Mass = 51.24 g

Molar mass of = 171.34 g/mol

The formula for the calculation of moles is shown below:

Thus,

Volume = 1.20 L

The expression for the molarity is:

Thus,

Considering

Given  that:

So,  

The volume of 0.24925M stock solution added = 0.40 L

i think its 100

i hope this !