Someone me with the application problems:

1) P = 116.75 psi

2) V = 0.565 L.

3) V = 373.33 ml

Explanation:

1) Given, the pressure in tire is 105 psi at 25°C = 298 K

and then it is moved to another place where temperature is -5°C = 268 K.

Now, as the volume of tire remained constant, from gas law,

= constant.

⇒ P₁T₂ = P₂T₁ .

⇒ 105×298 = P ×268.      ⇒ P = 116.75 psi .

2) Given, balloon with volume 0.55 L at 22°C  = 295 K is placed outside where the temperature is 30°C = 303 K and also pressure is constant

⇒From gas laws, = constant

⇒ 0.55 × 303 = V × 295.           ⇒ V = 0.565 L.

3) Given, pressure in balloon changes from 0.80 atm to 1.2 atm

   and initial volume is 560 ml.

   As the temperature remained constant, from gas laws,

    PV = constant.

⇒ 0.80 × 560 = 1.2 × V.              ⇒ V = 373.33 ml.

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