Calculate the number of moles of o2 produced using the ideal gas law. then, use this value to calculate the number of moles of hydrogen peroxide you began the experiment with. hint: use the balanced equation provided in the lab introduction.

Given data from the lab collated as 291.15k for Temperature, 0.061L for volume and 1atm pressure.

Initial hydrogen peroxide solution is 5ml with a weigh % concentration 6.6%

n=0.0025moles of oxygen AND 0.0097moles of H2O2 were present

Explanation:

2H2O2(aq)2H2O(I)+2O2(g)

Recall the idea gas equation

PV=nRT

n=PV/RT---(1) solving equation (1) using the data in the answer section above.

n=0.0025moles of oxygen is produced.

Recall that for every 100ml of solution you get 6.6g of hydrogen peroxide.

Your 5ml will thus contain

5ml*6.6g H2O2/100ml=0.33g

no of moles if H2O2=0.33/34.015=0.0097moles

i think slash and

air

in a tire you fill a tire with air

then a couple days later you check the air pressure in the tire

hope this mark me brainliest