Chemistry, 19.12.2019 22:31 mostman077

Elaborate on how the duet and octet rules relate to ion formation?
a) the duet rule or the octet rule state that atoms form ions in an effort to acquire valence electron configuration impermanence.
b) both the duet and octet rules reveal that atoms gain or lose electrons forming ions to achieve a more stable electron configuration.
c) ion formation only occur if the atom have a full duet electron configuration or full octet electron configuration of valence electrons.
d) formation of immutable noble-gas configuration ions results from atoms with ambiguous duet or octet configurations of valence electrons.

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Answer from: u8p4

B).Both the duet and octet rules reveal that atoms gain or lose electrons forming ions to achieve a more stable electron configuration.

Explanation:

Duet : The outermost shell of an element has two electron.

Octet : The outermost shell of an element has eight electron

According to Lewis Theory of bonding.

He suggested that atoms forms bond either by sharing of electron pair or by complete transfer of electron from one atom to other in order to achieve the stable atomic configuration.

Noble Gas configuration (stable atomic configuration) : When the outermost shell of an atom is fully filled(8 electron) , then it get stability and don't react with other element .E.g Ne = 10 electron = 1s(2) 2s(2) 2p(6) = 8 electron

Neon is stable elements.

Consider,Sodium element (Na) it has 11 electron = 1s(2) 2s(2) 2p(6) 3s(1) , If it looses 1 electron from 3s ,then it has 8 electron left (same as Ne).

So Na show (+1) valency .

Chlorine(Cl), it has 17 electron , 1s(2) 2s(2) 2p(6) 3s(2) 3p(5) , In order to achieve stability , it gain one electron and show (-1) valency.

Elaborate on how the duet and octet rules relate to ion formation? a) the duet rule or the octet r

Answer from: Quest

If a hydrogen atom is neutral, it must also have one electron. an oxygen atom (o) has an atomic number of eight (8). this means a neutral oxygen atom has eight protons and eight electrons. the element actium (ac) has an atomic number of 89, so it has 89 protons and 89 electrons in a neutral atom

Answer from: Quest

Answerthe half-reaction having the greatest tendency to occur at the anode: i₂(aq) + 2e⁻ ⇄ 2i⁻ ; e = +0.53 v====== $\begin{aligned} \text{i}_2\text{\footnotesize (aq)}+2\,\text{e}^{-} & \rightleftharpoons 2\,\text{i}^{-}\text{\footnotesize (aq)}& \text{e} & = +0.53\text{ v} \\ \text{co}^{3+}\text{\footnotesize (aq)} + \text{e}^{-} & \rightleftharpoons \text{co}^{2+}\text{\footnotesize (aq)} & \text{e} & = +1.80\text{ v} \\ \text{o}_2\text{\footnotesize (g)}+4\,\text{h}^{+}\text{\footnotesize (aq)} + 4\,\text{e}^{-} & \rightleftharpoons 2\,\text{h}_2\text{o}\text{\footnotesize(l)}& \text{e} & = +1.23\text{ v} \\ \end{aligned}$ oxidation occurs at the anode. we must therefore find the half-reaction with the greatest tendency to oxidize.the given values of e are reduction potentials (the form of the half-reactions are of reduction).the lower the reduction potential, the higher the potential to oxidize. the half-cell with the lowest reduction potential will have the greatest tendency to oxidize at the anode.the half-reaction having the greatest tendency must be i₂(aq) + 2e⁻ ⇄ 2i⁻ e = +0.53 vbecause its reduction potential is the lowest out of the three.

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Elaborate on how the duet and octet rules relate to ion formation?
a) the duet rule or the o...

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