Compound decomposes through the following unbalanced reaction in acidic media: mno2→ mno4-(s) + mn2+(s) balance this reaction and use the information to answer the following three (3) questions. 14. what is the reducing agent?
a) h+
b) h2o
c) mno2
d) mno4-
e) mn2+

C) MnO₂

Explanation:

If we write the semi equations (this is, for reduction and oxidation) we will have:

Oxidation: 2MnO₂ → MnO₄⁻ + Mn⁺²

Reduction: 2H₂O → H₂ + 2OH⁻

Then the final global reaction (just adding the two above hemi chemical reactions):

2MnO₂ + 2H₂O → MnO⁻₄ + Mn⁺² + H₂ + 2OH⁻ (in acidic media)

So, we have Mn⁺⁴ (from MnO₂) goes to Mn⁺⁷ and Mn⁺² (this is, Mn is oxidated) and H⁺ (from acidic media or H₂O) goes to H₂ (this is, it is reduced). So the reducing agent would be MnO₂

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