Balance the following chemical equation: \text{nh_4\text{no}_ 3 \rightarrow nh 4 no 3 →start text, n, h, end text, start subscript, 4, end subscript, start text, n, o, end text, start subscript, 3, end subscript, right arrow \text{n}_2 +n 2 +start text, n, end text, start subscript, 2, end subscript, plus \text{o}_2 +o 2 +start text, o, end text, start subscript, 2, end subscript, plus \text{h}_2\text{o}h 2 o

The balanced chemical equation is given as:

Explanation:

During the balancing of the chemical reaction, balance all the atoms of every atoms except oxygen element.

There are 2 nitrogen atoms on both sides. Nitrogen atom is balanced.

There are 4 hydrogen atoms on left side and 2 hydrogen atom on right side.Write 2 in front of to balance the hydrogen atoms.

Now ,see the number of oxygen atoms on both sides. Here on both sides oxygen atoms oxygen atom are same.

So, write 2 in front of , 2 in front of and 4 in front of .

All the atoms of all each and every element is balanced in the chemical equation.

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.