4nh3 + 5o2 -- 4no + 6h2o how many moles of oxygen gas are needed to react with 23 moles of ammonia

28.75 moles

Explanation:

Data Given:

no. of moles of ammonia (NH₃) = 23 moles

no. of moles of oxygen gas (O₂) = ?

Reaction given

                    4NH₃ + 5O₂ > 4NO + 6H₂O

Solution:

First we have to look at the reaction for moles details

                     4NH₃    +    5O₂   > 4NO + 6H₂O

                      4 mol       5 mol

So,

if 4 moles of ammonia (NH₃) react with 5 moles of oxygen gas (O₂) so how many moles of oxygen gas (O₂) will be react with 23 moles of ammonia (NH₃).

Apply Unity Formula

                       4 moles of NH₃ ≅ 5 moles of O₂

                       23 moles of NH₃ ≅ X moles of O₂

Do cross multiply

                      moles of O₂ = 5 mol x 23 mol / 4 mol

                      moles of O₂ = 28.75 mol

So the no. of moles of O₂ that react with 23 moles of NH₃ = 28.75 mol

fe 55.85 g/mol and h2o 18.02 g/mol.