Methane is also known as natural gas, and its combustion is a very common reaction: ch4 + 2 o2 → co2 + 2 h2o. remember that we can use stoichiometry if we know the correct coefficients. so, which of these conversion factors will not work for this reaction? note: all numbers located immediately after elemental symbols should be considered subscripts.
a. 1 mole o2 = 32.00 g
b. 2 mole h2o = 18.02 g
c. 2 mole o2 = 1 mole co2
d. 1 mole ch4 = 2 mole h2o
e. none of the above

2 mole H2O = 18.02 g will not work.

Explanation:

Let us check the options one by one:

1 mole of O2 weighs 32 g.

⇒Hence option A is correct.

1 mole of H2O weighs 18 g.

⇒Hence option B is wrong.

From the balanced equation we can say :

1 mole of CH4 reacts with 2 moles of O2 to give 1 mole of CO2 and 2 moles of H2O.

⇒Hence option C and D are correct.

Option B: 2 mole H2O = 18.02 g is not correct.

Explanation:

Step 1: The balanced equation

CH4 + 2O2 → CO2 + 2H2O

Step 2: Data given

Molar mass of O2 = 32 g/mol

Molar mass of H2O = 18.02 g/mol

Molar mass of CH4 = 16.04 g/mol

Step 3: Calculate number of mol

For 1 mol of CH4 we need 2 moles of O2 to produce 1 mol of CO2 and 2 moles of H2O

This means option C is correct: For 2 moles O2 consumed, we'll get 1 mol of CO2 produced.

Also Option D is corect: For 1 mole of CH4 we get 2 moles of H2O

Mass = moles * molar mass

Mass of 1 mole O2 = 1 mol * 32.00 g/mol = 32.00 grams

Mass of 2 moles H2O = 2 mol * 18.02 g/mol = 36.04 grams  (This means option B is not correct.)

Option B: 2 mole H2O = 18.02 g is not correct.

alienation, transformation, consumption, and the relativity of truth.

you can choose any one of these, they are all important themes.

these themes reflect the distinct sensibilities of both the modernist and postmodern aesthetic movements. (from google, you should paraphrase)

hope this !

- melanie

because of all the things that happen around the us, many people get into arguments which sadly could get physical, but we should actually make a change for that.