How many grams of nacl should be added to 500 g of water to produce a solution which freezes at –5.00 c? (the k f for water is 1.86°c/m.) provide step by step.

39.31 grams of NaCl

Explanation:

Let x be the mass of NaCl added.

Decrease in freezing point = ΔTf = 5°C

Kf for water = 1.86 °C/m

Molality of the solution = m =

i = Vant hoff factor  =

Formula for depression in freezing point:

ΔTf = i×Kf×m

i for NaCl = 2 (As NaCl dissociates into Na+ and Cl- ions in solution)

molar mass of NaCl = 58.5 g/mol

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