What mass will 33.6 l of oxygen gas (o2) have at stp ?

16 g

32 g

34 g

48 g

48 grams of O₂ occupy 33.6L at STP

Explanation:

Let's apply Ideal Gases Law to this situation:

STP = Standard conditions of T° and pressure

T° = 273K

Pressure = 1 atm

P .V = n . R . T

1 atm . 33.6L = n . 0.082 . 273K

(1 atm . 33.6L) / (0.082 . 273K) = n

1,50 moles = n

Now, we must find out the mass of O₂ with the molar mass

Molar mass . moles = Mass

32 g/m  . 1.5 moles = 48 g