Ablacksmith making a tool heats 525 grams of steel to 1230c . after hammering the steel ,she places it into a bucket of water to cool it. when she removes the steel from the water , it's a 50c . how much heat does the steel release if its specific heat capacity is 0.486 joules/gram degree celsius?

Q = 18625.95 j

Explanation:

Given data:

Mass of steel = 525 g

Initial temperature = 123 °C

Final temperature = 50 °C

Heat release by steel = ?

Specific heat capacity of steel = 0.486 j/g. °C

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT  = T2  - T1

ΔT  = 123°C - 50°C

ΔT  = 73°C

Q = m.c. ΔT

Q = 525 g.  0.486 j/g.°C . 73°C

Q = 18625.95 j

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