1.)
chemical equilibrium is described as being dynamic because
the mass of the re...
Chemistry, 17.12.2019 07:31 sciencefanfae7248
1.)
chemical equilibrium is described as being dynamic because
the mass of the reactants changes to equal the mass of the products
the concentration of the reactants changes to equal the mass of the products
opposing reactions are constantly occurring at an equal rate
it cannot be changed
3 points
2.)
a reversible reaction at equilibrium can counteract the stress of an increase in pressure by
favoring the formation of more moles of gaseous products
favoring the formation of fewer moles of gaseous products
favoring the formation of more liquid products
favoring the formation of more solid products
Answers: 1
Chemistry, 22.06.2019 04:30
Both josef loschmidt and amedeo avogadro contributed to our understanding of basic molecular numbers, sizes, and reaction ratios. neither scientist discovered “avogadro’s number” in the form we use it today (6.02 x 10 23). still, there’s a controversy over the name. research the contributions from these two scientists and read about how avogadro’s number got its name. briefly state what you think this number should be called, providing key details of each scientist’s contributions to this concept and a solid rationale for your case in naming the number.
Answers: 2
Chemistry, 22.06.2019 15:20
Water is initially present in a state where its molecules are far apart. during a change of state, its molecules slow down. which change of state has most likely taken place? from a gas to a liquid from a liquid to a gas from a solid to a liquid from a gas to a plasma
Answers: 1
Chemistry, 22.06.2019 21:50
Answer the questions about this reaction: nai(aq) + cl2(g) → nacl(aq) + i2(g) write the oxidation and reduction half-reactions: oxidation half-reaction: reduction half-reaction: based on the table of relative strengths of oxidizing and reducing agents (b-18), would these reactants form these products? write the balanced equation: answer options: a. 0/na -> +1/na+1e- b. nai(aq) + cl2(g) → nacl(aq) + i2(g) c. +1/na+1e- -> 0 /na d. -1/2i -> 0/i2+2e- e. no f. 4nai(aq) + cl2(g) → 4nacl(aq) + i2(g) g. 2nai(aq) + cl2(g) → 2nacl(aq) + i2(g) h. 4nai(aq) + 2cl2(g) → 4nacl(aq) + 2i2(g) i. nai(aq) + cl2(g) → nacl(aq) + i2(g) j. 0/cl2+2e -> -1/2cl- k. yes
Answers: 1
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