If 325 g of ammonia is used, what amount, in moles, of nitrogen monoxide will be produced in the
following equation: 4nh3(g) + 5o2(g) → 4no(g) + 6h2o(g)?

19.12 moles of NO will produced.

Explanation:

Given data:

Mass of ammonia = 325 g

Moles of NO produced = ?

Solution:

Chemical equation:

4NH₃ + 5O₂ → 4NO + 6H₂O

Number of moles of Ammonia:

Number of moles = mass/ molar mass

Number of moles = 325 g/ 17 g/mol

Number of moles = 19.12 mol

Now we will compare the moles of ammonia and NO.

                   NH₃              :                NO

                      4                :                 4

                     19.12           :              19.12

Thus 19.12 moles of NO will produced.