Determine the oxidation number (oxidation state) of each element in the following six compounds. (a) cuco_3 cu: + 2 c: +4 o: - 2 (b) ch_4 c: - 4 h: + 1 (c)if 1: + 1 f: - 1(d) ch_2ci_2 c: - 4 h: + 1 ci: - 1 the sum of the oxidation numbers in a compound is zero. since you know there are two h (oxidation state +1) and two cl (oxidation state -1), you can determine the oxidation state for c. (e) so_2 s: + 4 o: - 2 (f) {nh_4}_2 cro_4 h: + 3 n: - 1 o: - 6 cr: + 1