The t 1/2 of a certain radioisotope is 4 weeks what fraction of the original isotope remains after 12 weeks

The fraction of original isotope remaining after 12 weeks is 1/8 (0.125)

Explanation:

The half life of the radio-isotope = 4 weeks =

After n half lives, the fraction of original isotope remaining =

In 12 weeks, the number of half lives = 12/4 = 3 half lives

The fraction of original isotope remaining =

Hence, after 12 weeks, fraction of original isotope remaining is 1/8 (0.125)

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.