Assuming an equal mass of nitrogen in each compound, which oxide of nitrogen contains the greatest number of moles of oxygen atoms? n2o3n2o5no2no

N₂O₅

Explanation:

To compare the number of moles of oxygen atoms, we will refer them to the same mass (1 g) of N.

N₂O₃

In 1 mole of N₂O₃ we have 3 moles of atoms of O.

In 1 mole of N₂O₃ we have 28 g of N.

The ratio moles of O:mass of N is 3 mol O : 28 g N = 0.11 mol O : 1 g N

N₂O₅

In 1 mole of N₂O₅ we have 5 moles of atoms of O.

In 1 mole of N₂O₅ we have 28 g of N.

The ratio moles of O:mass of N is 5 mol O : 28 g N = 0.18 mol O : 1 g N

NO₂

In 1 mole of NO₂ we have 2 moles of atoms of O.

In 1 mole of NO₂ we have 14 g of N.

The ratio moles of O:mass of N is 2 mol O : 14 g N = 0.14 mol O : 1 g N

NO

In 1 mole of NO we have 1 mole of atoms of O.

In 1 mole of NO we have 14 g of N.

The ratio moles of O:mass of N is 1 mol O : 14 g N = 0.07 mol O : 1 g N

N₂O₅ is the one with the greatest number of moles of oxygen atoms per gram of N.