4fe(s)+3o2(g)→2fe2o3(s) how many grams of fe2o3 are produced when 12.0 of iron rusts

Mass = 10.1 g

Explanation:

Given data:

Mass of Fe₂O₃ produced = ?

Mass of iron rust = 12.0 g

Solution:

Chemical equation:

4Fe + 3O₂    →  2Fe₂O₃

Number of moles of iron:

Number of moles = mass/ molar mass

Number of moles = 12.0 g/ 55.85 g/mol

Number of moles = 0.215 mol

Now we will compare the moles of iron and Fe₂O₃ .

                     Fe            :          Fe₂O₃

                      4             :              2

                       0.215     :          2/4×0.125 = 0.063 mol

Mass of  Fe₂O₃ :

Mass = number of moles × molar mass

Mass = 0.063 mol × 159.7 g/mol

Mass = 10.1 g

atomic number of carbon is 6

electronic configuration of carbon is 1s²2s²2p²

orbital diagram of carbon is as shown here in the image.

for step 7 table c on the lab "newtons law of action"   the average time it took the car to travel .25 meters   was 1.92 seconds.

the average time it took the car to travel 0.50 meters was 2.61 seconds

hope this : )