For the reaction 8 h 2 s ( g ) − ⇀ ↽ − 8 h 2 ( g ) + s8 ( g ) 8h2s(g)↽−−⇀8h2(g)+s8(g) the equilibrium concentrations were found to be [ h 2 s ] = 0.250 m, [h2s]=0.250 m, [ h 2 ] = 0.600 m, [h2]=0.600 m, and [ s 8 ] = 0.750 m. [s8]=0.750 m. what is the equilibrium constant for this reaction

Kc = 826

Explanation:

For the equilibrium:

8 H₂S (g)        ⇄   8 H₂(g)   + S₈ (g)

the equilibrium constant is:

Kc = [ H₂ ] ⁸ x [ S₈ ] /  [H₂S]⁸

Kc = 0.600⁸ x 0.750 / (0.250)⁸ = 1.68 x 10⁻² x 0.750 / 1.53 x 10⁻⁵

                                                =  824

Be careful with raising to the power of 8 in your calculator.

first one is the correct answer

a. hope i'm right

explanation: