At a certain temperature, the k p kp for the decomposition of h 2 s h2s is 0.746 0.746 . h 2 s ( g ) − ⇀ ↽ − h 2 ( g ) + s ( g ) h2s(g)↽−−⇀h2(g)+s(g) initially, only h 2 s h2s is present at a pressure of 0.240 0.240 bar in a closed container. what is the total pressure in the container at equilibrium?

The total pressure of container at equilibrium is 0.431 bar

Explanation:

We are given:

Pressure of hydrogen sulfide = 0.240 bar

The given chemical equation follows:

Initial:            0.240

At eqllm:      0.240-x        x      x

The expression of for above equation follows:

We are given:

Putting values in above expression, we get:

Neglecting the negative value of 'x' because pressure cannot be negative.

So, the equilibrium pressure of hydrogen gas = x = 0.191 bar

The equilibrium pressure of sulfur gas = x = 0.191 bar

The equilibrium pressure of hydrogen sulfide gas = (0.240 - x) = (0.240 - 0.191) = 0.049 bar

Total pressure of the container at equilibrium =

Total pressure of the container at equilibrium = 0.191 + 0.191 + 0.049 = 0.431 bar

Hence, the total pressure of container at equilibrium is 0.431 bar

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