The combustion of ethane ( c 2 h 6 ) (c2h6) produces carbon dioxide and steam. 2 c 2 h 6 ( g ) + 7 o 2 ( g ) ⟶ 4 co 2 ( g ) + 6 h 2 o ( g ) 2c2h6(g)+7o2(g)⟶4co2(g)+6h2o(g) how many moles of co 2 co2 are produced when 5.80 mol 5.80 mol of ethane is burned in an excess of oxygen?

There is a production of 11.6 moles of CO₂

Explanation:

The reaction is this:

2C₂H₆(g)  +  7O₂(g)  ⟶  4CO₂(g)  +  6H₂O(g)

2 moles of ethane reacts with 7 moles of oxygen, to make 4 mol of dioxide and 6 moles of water vapor.

If the oxygen is in excess, we make the calculate with the ethane (limiting reactant)

2 moles of ethane produce 4 moles of dioxide

5.8 moles of ethane produce (5.8  .4)/2 = 11.6 moles

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