Be sure to answer all parts. cyclopropyl chloride has been prepared by the free-radical chlorination of cyclopropane. draw the products for each equation of the stepwise mechanism for this reaction. be sure to include lone pair(s) of electrons where necessary. part 1 out of 3 ca45304fix1 draw structure plussign

See explanation and picture

Explanation:

In the picture you have the mechanism and procedure of this reaction. Remember that this kind of reactions are given in 3 steps:

Step 1: Initiation

The reaction begins with the separation of the chlorine (Cl2) into two radicals (atoms with a single unpaired electron) by the addition of uv light.

Step 2: Propagation

The formation of the chlorine radicals, is immediately followed by the propogation steps--steps directly involved in the formation of the product. The first step is the abstraction of the hydrogen atom from the carbon, to form the radical CH2, with a lone ion, and H-Cl.

Step 3: termination

The termination involve the destruction of the free-radical intermediates, typically by two of them coming together.

See the picture for mechanism.

answer: i have one answer

acids are substances that ionize (break off) in an aqueous solution to produce hydrogen (h+) ions

explanation:

hope this and sorry i could only come up with one answer!

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol