In a certain industrial process involving a heterogeneous catalyst, the volume of the catalyst (in the shape of a sphere) is 10.0 cm3. if the sphere were broken down into eight spheres each having a volume of 1.25 cm3, and the reaction is run a second time, which of the following accurately characterizes the second run? choose all that apply a. the second run will be faster. b. the second run will be slower. c. the second run will have the same rate as the first. d. the second run has twice the surface area. e.the second run has eight times the surface area. f. the second run has 10 times the surface area

The second run will be faster - true, the increased surface area of catalyst will increase the rate of reaction

The second run will have the same rate as the first - possible, in case there is a factor other than catalyst limiting the reaction

The second run has twice the surface area - yes, 44 sqcm to 22 sqcm

Explanation:

A catalyst is a material which speeds up a reaction without being consumed in the process. A heterogeneous catalyst is one which is of a different phase than the reactants. The effectiveness of a catalyst is dependent on the available surface area. The first step for this question is to determine the total available surface area of catalyst in both processes.

Step 1: Determine radius of large sphere

Step 2: Determine surface area of large sphere

Step 3: Determine radius of small sphere

Step 4: Determine surface area of small sphere

Step 5: Determine total surface area of 8 small spheres

- Surface area of 1 large sphere

- Surface area of 8 small spheres

Options:

your answer would be “dry”