Agas occupied 23.55 l at 118.2 celsius. at what temp would the gas occupied 43.8 l

The gas occupies 43.8 L at a temperature of 219.8 °C

Explanation:

Step 1: Data given

Volume of the gas = 23.55L

Temperature = 118.2 °C

New volume = 43.8 L

Step 2: Calculate changed temperature

(P1*V1)/T1 = (P2*V2)/T2

Let's assume the pressure stays constant, then we have:

V1/T1 = V2/T2

⇒ with V1 = the initial volume = 23.55L

⇒ with T1 = the initial temperature = 118.2 °C

⇒ with V2 = the changed volume = 43.8 L

⇒ with T2 = the changed temperature = TO BE DETERMINED

23.55L/118.2°C = 43.8 L / T2

T2 = 219.8 °C

The gas occupies 43.8 L at a temperature of 219.8 °C

it is to be noted that an alpha particle is an helium nucleus. so it contains 2 protons 2 neutrons and has a mass number of 4. when alpha decay particles are ejected from the nucleus it gets transformed into an atom which has atomic number less than 2 and a mass number less than 4.

an equation that could represent alpha decay is radium 226 decay of alpha particle forms radon 222.

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it's c (engineer's do their work with mechanical stuff not on any living being)