If the pressure, volume, and temperature of a gas are known, which can most lik
was
the molar amount of the gas
o the partial pressure of the gas
o the standard temperature and pressure
o the molar mass

The molar amount of the gas.

Explanation:

If the pressure, volume, and temperature of a gas are known than molar amount can be determine.

Formula:

PV = nRT

P = pressure

V = volume

R = general gas constant

T = temperature

n = number of moles

Example:

V = 2 L, P = 1 atm , T = 273 K , R = 0.0821 atm. L/mol.K

n = PV/RT

n = 1 atm. 2 L / 0.0821 atm. L/mol.K . 273 K

n = 2 / 22.413 /mol

n = 0.09 mol

3 hours because it is a decent distance.

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.