Hydrochloric acid and calcium carbonate react to form calcium chloride, carbon dioxide, and water. if you being with 1.25 l of 1.20 m calcium carbonate and a stoichiometric amount of hydrochloric acid, how many grams of carbon dioxide will be formed

44.01 grams of carbon dioxide will be formed

Explanation:

This is the balance equation:

2HCl (aq)  +  CaCO₃ (aq)  →  CaCl₂ (aq)  +  CO₂ (g)  + H₂O (l)

Firstly, let's find out the moles for the salt, in the reactants.

Molarity . volume = Moles

1.2 mol/L . 1.25L = 1.5 moles

The stoichiometric amount of hydrochloric acid is 2.

Ratio between reactants is 2:1

If I have 2 moles of HCl, I need 1 mol of carbonate. I have 1.5 moles, so the salt is in excess and the limiting is the HCl.

Ratio between HCl and CO₂ is 2:1

If I have 2 moles of HCl, I make 1 mol of CO₂

The grams formed are just, the molar mass.

44.01 g

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water and alcohols have similar properties because water molecules contain hydroxyl groups that can form hydrogen bonds with other water molecules and with alcohol molecules, and likewise alcohol molecules can form hydrogen bonds with other alcohol molecules as well as with water.