Combustion analysis of toluene, a common organic solvent, gives 6.45 mg of co2 and 1.51 mg of h2o. if the compound contains only carbon and hydrogen, what is its empirical formula?

Empirical formula -

Explanation:

From the given,

Mass of = 6.45 mg= 0.00645 g

Molar mass of carbon = 12 g/mol

Molar mass of = 44 g/mol

Given mass of = 1.51 mg= 0.00151 g

Molar mass of water = 18 g/mol

Molar mass of hydrogen = 1.0 g/mol

1:1.4

Those two values are multiplied by two.(molar ratio -7)

Therefore, empirical formula -

answerambulatory;