Enter your answer in the provided box. the formula that governs the depression of freezing point and elevation of boiling point for a solution consisting of a solute dissolved in a solvent is: where: at = the temperature change between a pure solvent and its solution i = the number of species per mole of solute that are dissolved in the solvent (e. g., i = 1 for a non-ionic solute that does not break apart into ions, i = 2 for an ionic solute such as br that breaks apart into two ions, k* and br, and so on) a constant related to the solvent m = molality of the solute (molality, m = moles of solute / kg of solvent) using the above equation, how many grams of salt (cacl2) would need to be added to 1 l of water in order for the boiling point of the solution to reach 103.5 °c? assume that the density of water is 1.0 g/ml and that cacl2 completely dissociates into three ions − i. e., a ca2+ ion and two cl− ions. the boiling point constant, kb, for water is 0.515 °c/m.

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

b) nuclear ive learned that in a pedtrodic table