What is your question? high school chemistry 5+3 pts to ensure that the air in the shuttle remains free of excess co2, engineers test the air-purification system. they combine 1.000 × 103 g lioh with 8.80 × 1 02 g co2. the reaction produces 3.25 × 102 g h2o. what is the limiting reactants in this test reaction

The balanced reaction is:

2LiOH + CO2 = Li2CO3 + H2O

We are given the amount of the reactants to be reacted. This will be the starting point of our calculations. To determine the limiting reactant, we convert the amounts from grams to moles.

1.000 × 10^3 g LiOH  (1 mol / 25.95 g) = 38.54 mol LiOH

8.80 × 10^2 g CO2 ( 1mol / 44.01 g) = 20.00 mol CO2

From the balanced reaction, the molar ratio of the reactants is 2:1. This means that every two mole of lithium hydroxide, 1 mole of carbon dioxide is needed. It is clear that, from the given amounts, CO2 is the limiting reactant.

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.