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calculate the energy of a gamma ray photon with a frequency of 6.0 x 10^22

E = 39.78 ×10⁻¹²  j

Explanation:

Given data:

Frequency of photon = 6.0×10²² s⁻¹

Energy of photon = ?

Solution:

Formula:

E = h.f

E = 6.63 ×10⁻³⁴ m² kg/s × 6.0×10²² s⁻¹

E = 39.78 ×10⁻¹² Kg. m²/s²

Kg. m²/s² = j

E = 39.78 ×10⁻¹²  j

answer; i believe that the correct answer is (a) potassium(k)

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explanation: