Calculate the ph of a solution prepared by mixing 0.080 0 mol of chloroacetic acid plus 0.040 0 mol of sodium chloroacetate in 1.00 l of water.

Explanation:

The given data is as follows.

        Moles of chloroacetic acid = 0.08 mol

        Moles of sodium chloroacetate = 0.04 mol

So, first calculate the molarity of chloroacetic acid and sodium chloroacetate as follows.

         Molarity =

Molarity of chloroacetic acid =

                               =

                               = 0.08 M

 Molarity of sodium chloroacetate =

                               =

                               = 0.04 M    

Now, according to the Henderson-Hasselbalch equation,

         pH =

               =

               =

              = 2.564

Thus, we can conclude that pH of given solution is 2.546.