When copper combines with oxygen, copper (ii) oxide is formed. if 7.0 mol of copper reacts with 4.0 mil of oxygen, what amount of the excess reactant remains?

I believe that there are .5 moles of O₂ left over.

Explanation: O₂+ 2 Cu= 2 CO₂+ 2 H₂O. With 7 moles of Cu you can get 7 moles of CuO. But, with 4 moles of O₂ you can get 8 moles of CuO, so O₂ is the limiting reactant. Thus, you would have to use 7 moles of Cu in order to determine the moles of O₂ and you get 3.5 moles of O₂. 4 moles- 3.5 moles =.5 moles

a  solution  is always transparent, light passes through with no scattering from solute particles which are molecule in size. the  solution  is homogeneous and does not settle out. a colloid is intermediate between asolution  and a  suspension. while asuspension  will separate out a colloid will not.

elements make up everything, and they combine to make compounds.

the answer is c