Amixture of he he , n 2 n2 , and ar ar has a pressure of 24.1 24.1 atm at 28.0 28.0 °c. if the partial pressure of he he is 3013 3013 torr and that of ar ar is 2737 2737 mm hg, what is the partial pressure of n 2 n2

16.5 atm

Explanation:

A mixture of He, N₂, and Ar has a pressure of 24.1 atm at 28.0 °C. If the partial pressure of He is 3013 torr and that of Ar is 2737 mm Hg, what is the partial pressure of N₂?

The total pressure of a gaseous mixture is equal to the sum of the partial pressures.

P = pHe + pN₂ + pAr

pN₂ = P - pHe - pAr [1]

We need to express pHe and pAr in atm.

From [1],

pN₂ = 24.1 atm - 3.96 atm - 3.60 atm = 16.5 atm

water at room temperature is flowing through a pipe with pressure taps located 10 ft apart along one section of the pipe, which are connected to a mercury (s=13.6) manometer.