When a metal was exposed to light at a frequency of 3.64× 1015 s–1, electrons were emitted with a kinetic energy of 5.80× 10–19 j. what is the maximum number of electrons that could be ejected from this metal by a burst of light (at some other frequency) with a total energy of 8.66× 10–7 j?

Answer :  The maximum number of electrons released

Explanation : Given,

Frequency =

Kinetic energy =

Total energy =

First we have to calculate the work function of the metal.

Formula used :

where,

K.E = kinetic energy

h = Planck's constant =

= frequency  

w = work function

Now put all the given values in this formula, we get the work function of the metal.

By rearranging the terms, we get

Therefore, the works function of the metal is,

Now we have to calculate the maximum number of electrons released.

The maximum number of electrons released =

Therefore, the maximum number of electrons released is

metals are good conductor of electricity. it has free electrons on their surface. according to electron pool theory, each atom present in a metal crystal losses all of its valence electron and as a result a pool of free is form. these pool of electrons are free to move and   conduct electricity easily   while making metal as good conductor.

the correct answer is a. the ability of electrons to flow throughout the metal.

if it's not useful, feel free to report for mistake in answer.

it’s previous models   because when i picked that son of a gun’s answer it was wrong look for previous models because they might make it a different letter