Using the thermodynamic information in the aleks data tab, calculate the boiling point of titanium tetrachloride . round your answer to the nearest degree.

The boiling point is 308.27 K (35.27°C)

Explanation:

The chemical reaction for the boiling of titanium tetrachloride is shown below:

Ti ⇒ Ti

ΔH° (Ti) = -804.2 kJ/mol

ΔH° (Ti) = -763.2 kJ/mol

Therefore,

ΔH° = ΔH° (Ti) - ΔH° (Ti) = -763.2 - (-804.2) = 41 kJ/mol = 41000 J/mol

Similarly,

s°(Ti) = 221.9 J/(mol*K)

s°(Ti) = 354.9 J/(mol*K)

Therefore,

s° = s° (Ti) - s°(Ti) = 354.9 - 221.9 = 133 J/(mol*K)

Thus, T = ΔH° /s° = [41000 J/mol]/[133 J/(mol*K)] = 308. 27 K or 35.27°C

Therefore, the boiling point of titanium tetrachloride is 308.27 K or 35.27°C.

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.