The enthalpy of fusion of h2o (s) at its normal melting point is 6.01 kj/mol. what is the entropy change for freezing 1 mole of water at this temperature?

22.01J/Kmol

Explanation:

The parameters given in this question are;

Enthalpy (H) = 6.01 kJ/mol.

Number of moles = 1

Entropy change (S) = ?

The formular relationship between entropy and enthalpy is given as;

ΔS=ΔH/T

Temperature for water at freezing point = 0C + 273 = 273 K (converting to Kelvin)

ΔS = 6.01/273

ΔS = 0.0220kJ/Kmol

ΔS = 0.02201 * 1000 = 22.01J/Kmol