Chemistry, 05.12.2019 23:31 carlinryan
Using the equations 2 c₆h₆ (l) + 15 o₂ (g) → 12 co₂ (g) + 6 h₂o (g)∆h° = -6271 kj/mol c (s) + o₂ (g) → co₂ (g) ∆h° = -393.5 kj/mol 2 h₂ (g) + o₂ (g) → 2 h₂o (g) ∆h° = -483.6 kj/mol determine the enthalpy for the reaction 6 c (s) + 3 h₂ (g) → c₆h₆ (l).
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Using the equations 2 c₆h₆ (l) + 15 o₂ (g) → 12 co₂ (g) + 6 h₂o (g)∆h° = -6271 kj/mol c (s) + o₂ (g)...
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