Asolution is made by mixing equal masses of methanol, ch 4 o , ch4o, and ethanol, c 2 h 6 o . c2h6o. determine the mole fraction of each component to at least three significant figures.
x meth = x eth = xeth=

The mole fraction of methanol

Xmeth= 0.59

The mole fraction of ethanol

Xeth = 0.41

Explanation:

Mole fraction of a component can be determined by:

Xi = moles of i / total moles of the components the components

Where i indicates the component

An equal mass of 100.0g is assumed for both methanol and ethanol

Molar mass of Methanol (CH4O)

= (1*12) + (4*1) +(1*16) =32g/mol

Mole of Methanol = mass of methanol /molar mass of methanol

=100/32 = 3.13mol.

Molar mass of ethanol ( C2H6O)

= (2*12)+(6*1)+(1*16) = 46.0g/mol

Mole of ethanol = 100/46

= 2.17mol.

Mole fraction of methanol (Xmeth)

= moles of methanol / total moles

Xmeth = 3.13/(3.13+2.17)

Xmeth = 0.59

Mole fraction of ethanol (Xeth)

= moles of ethanol /total moles

= 2.17/((3.13+2.17)

Xeth= 0.41

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.