A100 g piece of aluminum is heated to 90°c. it is then dropped into water to bring its temperature down to 20°c. the heat transferred to water is 6300 j. what is the specific heat capacity of aluminum?

c = 0.9 j/g. °C

Explanation:

Given data:

Mass of aluminium = 100 g

Initial temperature = 90 °C

Final temperature = 20°C

Heat transfer = 6300 J

Specific heat of aluminium = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

The Q will negative because metal release the heat.

c = Q / m. ΔT

ΔT  = t2 - t1

ΔT  = 20°C - 90 °C

ΔT  = -70 °C

c = -6300 j/ 100 g.-70°C

c = -6300 j/ -7000 g.°C

c = 0.9 j/g. °C

the ratio of the conjugate base to the acid required to attain the desired ph.

explanation: